47+(6x-4)=101

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Solution for 47+(6x-4)=101 equation: 



47+(6x-4)=101

We move all terms to the left:

47+(6x-4)-(101)=0

We add all the numbers together, and all the variables

(6x-4)-54=0

We get rid of parentheses

6x-4-54=0

We add all the numbers together, and all the variables

6x-58=0

We move all terms containing x to the left, all other terms to the right

6x=58

x=58/6

x=9+2/3

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