46-(3c+4)=2(c+6)+2

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Solution for 46-(3c+4)=2(c+6)+2 equation: 



46-(3c+4)=2(c+6)+2

We move all terms to the left:

46-(3c+4)-(2(c+6)+2)=0

We get rid of parentheses

-3c-(2(c+6)+2)-4+46=0



We calculate terms in parentheses: -(2(c+6)+2), so:

2(c+6)+2

We multiply parentheses

2c+12+2

We add all the numbers together, and all the variables

2c+14

Back to the equation:

-(2c+14)



We add all the numbers together, and all the variables

-3c-(2c+14)+42=0

We get rid of parentheses

-3c-2c-14+42=0

We add all the numbers together, and all the variables

-5c+28=0

We move all terms containing c to the left, all other terms to the right

-5c=-28

c=-28/-5

c=5+3/5

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