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45b+41/2b=540
We move all terms to the left:
45b+41/2b-(540)=0
Domain of the equation: 2b!=0We multiply all the terms by the denominator
b!=0/2
b!=0
b∈R
45b*2b-540*2b+41=0
Wy multiply elements
90b^2-1080b+41=0
a = 90; b = -1080; c = +41;
Δ = b2-4ac
Δ = -10802-4·90·41
Δ = 1151640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1151640}=\sqrt{36*31990}=\sqrt{36}*\sqrt{31990}=6\sqrt{31990}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1080)-6\sqrt{31990}}{2*90}=\frac{1080-6\sqrt{31990}}{180} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1080)+6\sqrt{31990}}{2*90}=\frac{1080+6\sqrt{31990}}{180} $
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