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45=3x*4x+1
We move all terms to the left:
45-(3x*4x+1)=0
We get rid of parentheses
-3x*4x-1+45=0
We add all the numbers together, and all the variables
-3x*4x+44=0
Wy multiply elements
-12x^2+44=0
a = -12; b = 0; c = +44;
Δ = b2-4ac
Δ = 02-4·(-12)·44
Δ = 2112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2112}=\sqrt{64*33}=\sqrt{64}*\sqrt{33}=8\sqrt{33}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{33}}{2*-12}=\frac{0-8\sqrt{33}}{-24} =-\frac{8\sqrt{33}}{-24} =-\frac{\sqrt{33}}{-3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{33}}{2*-12}=\frac{0+8\sqrt{33}}{-24} =\frac{8\sqrt{33}}{-24} =\frac{\sqrt{33}}{-3} $
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