450=b-3/2b-(2b-90)-(b+45)

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Solution for 450=b-3/2b-(2b-90)-(b+45) equation:



450=b-3/2b-(2b-90)-(b+45)
We move all terms to the left:
450-(b-3/2b-(2b-90)-(b+45))=0
Domain of the equation: 2b-(2b-90)-(b+45))!=0
b∈R
We multiply all the terms by the denominator
-(b-3+450*2b-(2b-90)-(b+45))=0
We calculate terms in parentheses: -(b-3+450*2b-(2b-90)-(b+45)), so:
b-3+450*2b-(2b-90)-(b+45)
determiningTheFunctionDomain b+450*2b-(2b-90)-(b+45)-3
Wy multiply elements
b+900b-(2b-90)-(b+45)-3
We get rid of parentheses
b+900b-2b-b+90-45-3
We add all the numbers together, and all the variables
898b+42
Back to the equation:
-(898b+42)
We get rid of parentheses
-898b-42=0
We move all terms containing b to the left, all other terms to the right
-898b=42
b=42/-898
b=-21/449

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