450=3,000(r)(2)

Solution for 450=3,000(r)(2) equation:

450=3.000(r)(2)

We move all terms to the left:

450-(3.000(r)(2))=0

We add all the numbers together, and all the variables

-(+3.000r^2)+450=0

We get rid of parentheses

-3.000r^2+450=0

We add all the numbers together, and all the variables

-3r^2+450=0

a = -3; b = 0; c = +450;
Δ = b2-4ac
Δ = 02-4·(-3)·450
Δ = 5400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5400}=\sqrt{900*6}=\sqrt{900}*\sqrt{6}=30\sqrt{6}$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30\sqrt{6}}{2*-3}=\frac{0-30\sqrt{6}}{-6}
=-\frac{30\sqrt{6}}{-6}
=-\frac{5\sqrt{6}}{-1}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30\sqrt{6}}{2*-3}=\frac{0+30\sqrt{6}}{-6}
=\frac{30\sqrt{6}}{-6}
=\frac{5\sqrt{6}}{-1}
$