45-(6x2)=-11

Solution for 45-(6x2)=-11 equation:

45-(6x^2)=-11

We move all terms to the left:

45-(6x^2)-(-11)=0

We add all the numbers together, and all the variables

-6x^2+56=0

a = -6; b = 0; c = +56;
Δ = b2-4ac
Δ = 02-4·(-6)·56
Δ = 1344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1344}=\sqrt{64*21}=\sqrt{64}*\sqrt{21}=8\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{21}}{2*-6}=\frac{0-8\sqrt{21}}{-12}
=-\frac{8\sqrt{21}}{-12}
=-\frac{2\sqrt{21}}{-3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{21}}{2*-6}=\frac{0+8\sqrt{21}}{-12}
=\frac{8\sqrt{21}}{-12}
=\frac{2\sqrt{21}}{-3}
$