45-(3+7y-2y-8)=-10y+25-(7y-7-6y+18)

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Solution for 45-(3+7y-2y-8)=-10y+25-(7y-7-6y+18) equation: 



45-(3+7y-2y-8)=-10y+25-(7y-7-6y+18)

We move all terms to the left:

45-(3+7y-2y-8)-(-10y+25-(7y-7-6y+18))=0

We add all the numbers together, and all the variables

-(5y-5)-(-10y+25-(y+11))+45=0

We get rid of parentheses

-5y-(-10y+25-(y+11))+5+45=0



We calculate terms in parentheses: -(-10y+25-(y+11)), so:

-10y+25-(y+11)

determiningTheFunctionDomain
-10y-(y+11)+25

We get rid of parentheses

-10y-y-11+25

We add all the numbers together, and all the variables

-11y+14

Back to the equation:

-(-11y+14)



We add all the numbers together, and all the variables

-5y-(-11y+14)+50=0

We get rid of parentheses

-5y+11y-14+50=0

We add all the numbers together, and all the variables

6y+36=0

We move all terms containing y to the left, all other terms to the right

6y=-36

y=-36/6

y=-6

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