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45+3/8x=x
We move all terms to the left:
45+3/8x-(x)=0
Domain of the equation: 8x!=0We add all the numbers together, and all the variables
x!=0/8
x!=0
x∈R
-1x+3/8x+45=0
We multiply all the terms by the denominator
-1x*8x+45*8x+3=0
Wy multiply elements
-8x^2+360x+3=0
a = -8; b = 360; c = +3;
Δ = b2-4ac
Δ = 3602-4·(-8)·3
Δ = 129696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{129696}=\sqrt{16*8106}=\sqrt{16}*\sqrt{8106}=4\sqrt{8106}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(360)-4\sqrt{8106}}{2*-8}=\frac{-360-4\sqrt{8106}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(360)+4\sqrt{8106}}{2*-8}=\frac{-360+4\sqrt{8106}}{-16} $
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