45+3(2x-10)=30-2(5x+2)

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Solution for 45+3(2x-10)=30-2(5x+2) equation: 



45+3(2x-10)=30-2(5x+2)

We move all terms to the left:

45+3(2x-10)-(30-2(5x+2))=0

We multiply parentheses

6x-(30-2(5x+2))-30+45=0



We calculate terms in parentheses: -(30-2(5x+2)), so:

30-2(5x+2)

determiningTheFunctionDomain
-2(5x+2)+30

We multiply parentheses

-10x-4+30

We add all the numbers together, and all the variables

-10x+26

Back to the equation:

-(-10x+26)



We add all the numbers together, and all the variables

6x-(-10x+26)+15=0

We get rid of parentheses

6x+10x-26+15=0

We add all the numbers together, and all the variables

16x-11=0

We move all terms containing x to the left, all other terms to the right

16x=11

x=11/16

x=11/16

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