44=(a+10)2a

Solution for 44=(a+10)2a equation:

44=(a+10)2a

We move all terms to the left:

44-((a+10)2a)=0


We calculate terms in parentheses: -((a+10)2a), so:

(a+10)2a

We multiply parentheses

2a^2+20a

Back to the equation:

-(2a^2+20a)


We get rid of parentheses

-2a^2-20a+44=0

a = -2; b = -20; c = +44;
Δ = b2-4ac
Δ = -202-4·(-2)·44
Δ = 752
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{752}=\sqrt{16*47}=\sqrt{16}*\sqrt{47}=4\sqrt{47}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4\sqrt{47}}{2*-2}=\frac{20-4\sqrt{47}}{-4}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4\sqrt{47}}{2*-2}=\frac{20+4\sqrt{47}}{-4}
$