4453=(3x)+(3x+11)+(3x+11)2+x

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Solution for 4453=(3x)+(3x+11)+(3x+11)2+x equation: 



4453=(3x)+(3x+11)+(3x+11)2+x

We move all terms to the left:

4453-((3x)+(3x+11)+(3x+11)2+x)=0



We calculate terms in parentheses: -(3x+(3x+11)+(3x+11)2+x), so:

3x+(3x+11)+(3x+11)2+x

We add all the numbers together, and all the variables

4x+(3x+11)+(3x+11)2

We multiply parentheses

4x+(3x+11)+6x+22

We get rid of parentheses

4x+3x+6x+11+22

We add all the numbers together, and all the variables

13x+33

Back to the equation:

-(13x+33)



We get rid of parentheses

-13x-33+4453=0

We add all the numbers together, and all the variables

-13x+4420=0

We move all terms containing x to the left, all other terms to the right

-13x=-4420

x=-4420/-13

x=+340

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