44-3(3c+4)=4(c+6)+c

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Solution for 44-3(3c+4)=4(c+6)+c equation: 



44-3(3c+4)=4(c+6)+c

We move all terms to the left:

44-3(3c+4)-(4(c+6)+c)=0

We multiply parentheses

-9c-(4(c+6)+c)-12+44=0



We calculate terms in parentheses: -(4(c+6)+c), so:

4(c+6)+c

We add all the numbers together, and all the variables

c+4(c+6)

We multiply parentheses

c+4c+24

We add all the numbers together, and all the variables

5c+24

Back to the equation:

-(5c+24)



We add all the numbers together, and all the variables

-9c-(5c+24)+32=0

We get rid of parentheses

-9c-5c-24+32=0

We add all the numbers together, and all the variables

-14c+8=0

We move all terms containing c to the left, all other terms to the right

-14c=-8

c=-8/-14

c=4/7

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