44-(3c+4)=2(c+5)+c

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Solution for 44-(3c+4)=2(c+5)+c equation: 


Simplifying
44 + -1(3c + 4) = 2(c + 5) + c

Reorder the terms:
44 + -1(4 + 3c) = 2(c + 5) + c
44 + (4 * -1 + 3c * -1) = 2(c + 5) + c
44 + (-4 + -3c) = 2(c + 5) + c

Combine like terms: 44 + -4 = 40
40 + -3c = 2(c + 5) + c

Reorder the terms:
40 + -3c = 2(5 + c) + c
40 + -3c = (5 * 2 + c * 2) + c
40 + -3c = (10 + 2c) + c

Combine like terms: 2c + c = 3c
40 + -3c = 10 + 3c

Solving
40 + -3c = 10 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
40 + -3c + -3c = 10 + 3c + -3c

Combine like terms: -3c + -3c = -6c
40 + -6c = 10 + 3c + -3c

Combine like terms: 3c + -3c = 0
40 + -6c = 10 + 0
40 + -6c = 10

Add '-40' to each side of the equation.
40 + -40 + -6c = 10 + -40

Combine like terms: 40 + -40 = 0
0 + -6c = 10 + -40
-6c = 10 + -40

Combine like terms: 10 + -40 = -30
-6c = -30

Divide each side by '-6'.
c = 5

Simplifying
c = 5

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