43=7+3(5+2v)

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Solution for 43=7+3(5+2v) equation: 



43=7+3(5+2v)

We move all terms to the left:

43-(7+3(5+2v))=0

We add all the numbers together, and all the variables

-(7+3(2v+5))+43=0



We calculate terms in parentheses: -(7+3(2v+5)), so:

7+3(2v+5)

determiningTheFunctionDomain
3(2v+5)+7

We multiply parentheses

6v+15+7

We add all the numbers together, and all the variables

6v+22

Back to the equation:

-(6v+22)



We get rid of parentheses

-6v-22+43=0

We add all the numbers together, and all the variables

-6v+21=0

We move all terms containing v to the left, all other terms to the right

-6v=-21

v=-21/-6

v=3+1/2

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