43=3x+4(2x-3)

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Solution for 43=3x+4(2x-3) equation: 



43=3x+4(2x-3)

We move all terms to the left:

43-(3x+4(2x-3))=0



We calculate terms in parentheses: -(3x+4(2x-3)), so:

3x+4(2x-3)

We multiply parentheses

3x+8x-12

We add all the numbers together, and all the variables

11x-12

Back to the equation:

-(11x-12)



We get rid of parentheses

-11x+12+43=0

We add all the numbers together, and all the variables

-11x+55=0

We move all terms containing x to the left, all other terms to the right

-11x=-55

x=-55/-11

x=+5

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