435=107+3b

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Solution for 435=107+3b equation: 



435=107+3b

We move all terms to the left:

435-(107+3b)=0

We add all the numbers together, and all the variables

-(3b+107)+435=0

We get rid of parentheses

-3b-107+435=0

We add all the numbers together, and all the variables

-3b+328=0

We move all terms containing b to the left, all other terms to the right

-3b=-328

b=-328/-3

b=109+1/3

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