435=(25+x)+3X

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Solution for 435=(25+x)+3X equation: 



435=(25+x)+3x

We move all terms to the left:

435-((25+x)+3x)=0

We add all the numbers together, and all the variables

-((x+25)+3x)+435=0



We calculate terms in parentheses: -((x+25)+3x), so:

(x+25)+3x

We add all the numbers together, and all the variables

3x+(x+25)

We get rid of parentheses

3x+x+25

We add all the numbers together, and all the variables

4x+25

Back to the equation:

-(4x+25)



We get rid of parentheses

-4x-25+435=0

We add all the numbers together, and all the variables

-4x+410=0

We move all terms containing x to the left, all other terms to the right

-4x=-410

x=-410/-4

x=102+1/2

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