43+(3x+18)+(6x-18)=180

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Solution for 43+(3x+18)+(6x-18)=180 equation: 



43+(3x+18)+(6x-18)=180

We move all terms to the left:

43+(3x+18)+(6x-18)-(180)=0

We add all the numbers together, and all the variables

(3x+18)+(6x-18)-137=0

We get rid of parentheses

3x+6x+18-18-137=0

We add all the numbers together, and all the variables

9x-137=0

We move all terms containing x to the left, all other terms to the right

9x=137

x=137/9

x=15+2/9

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