43(x-5)=2(x+5)

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Solution for 43(x-5)=2(x+5) equation: 



43(x-5)=2(x+5)

We move all terms to the left:

43(x-5)-(2(x+5))=0

We multiply parentheses

43x-(2(x+5))-215=0



We calculate terms in parentheses: -(2(x+5)), so:

2(x+5)

We multiply parentheses

2x+10

Back to the equation:

-(2x+10)



We get rid of parentheses

43x-2x-10-215=0

We add all the numbers together, and all the variables

41x-225=0

We move all terms containing x to the left, all other terms to the right

41x=225

x=225/41

x=5+20/41

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