42=8(3-k)+6(k-3)

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Solution for 42=8(3-k)+6(k-3) equation: 



42=8(3-k)+6(k-3)

We move all terms to the left:

42-(8(3-k)+6(k-3))=0

We add all the numbers together, and all the variables

-(8(-1k+3)+6(k-3))+42=0



We calculate terms in parentheses: -(8(-1k+3)+6(k-3)), so:

8(-1k+3)+6(k-3)

We multiply parentheses

-8k+6k+24-18

We add all the numbers together, and all the variables

-2k+6

Back to the equation:

-(-2k+6)



We get rid of parentheses

2k-6+42=0

We add all the numbers together, and all the variables

2k+36=0

We move all terms containing k to the left, all other terms to the right

2k=-36

k=-36/2

k=-18

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