42=7(x-3)+7(x-5)

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Solution for 42=7(x-3)+7(x-5) equation: 



42=7(x-3)+7(x-5)

We move all terms to the left:

42-(7(x-3)+7(x-5))=0



We calculate terms in parentheses: -(7(x-3)+7(x-5)), so:

7(x-3)+7(x-5)

We multiply parentheses

7x+7x-21-35

We add all the numbers together, and all the variables

14x-56

Back to the equation:

-(14x-56)



We get rid of parentheses

-14x+56+42=0

We add all the numbers together, and all the variables

-14x+98=0

We move all terms containing x to the left, all other terms to the right

-14x=-98

x=-98/-14

x=+7

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