42=2(z-53)

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Solution for 42=2(z-53) equation: 



42=2(z-53)

We move all terms to the left:

42-(2(z-53))=0



We calculate terms in parentheses: -(2(z-53)), so:

2(z-53)

We multiply parentheses

2z-106

Back to the equation:

-(2z-106)



We get rid of parentheses

-2z+106+42=0

We add all the numbers together, and all the variables

-2z+148=0

We move all terms containing z to the left, all other terms to the right

-2z=-148

z=-148/-2

z=+74

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