42=1x-4(1x-1)

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Solution for 42=1x-4(1x-1) equation: 



42=1x-4(1x-1)

We move all terms to the left:

42-(1x-4(1x-1))=0

We add all the numbers together, and all the variables

-(1x-4(x-1))+42=0



We calculate terms in parentheses: -(1x-4(x-1)), so:

1x-4(x-1)

We add all the numbers together, and all the variables

x-4(x-1)

We multiply parentheses

x-4x+4

We add all the numbers together, and all the variables

-3x+4

Back to the equation:

-(-3x+4)



We get rid of parentheses

3x-4+42=0

We add all the numbers together, and all the variables

3x+38=0

We move all terms containing x to the left, all other terms to the right

3x=-38

x=-38/3

x=-12+2/3

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