42=(3x-2)*2x

Solution for 42=(3x-2)*2x equation:

42=(3x-2)*2x

We move all terms to the left:

42-((3x-2)*2x)=0


We calculate terms in parentheses: -((3x-2)*2x), so:

(3x-2)*2x

We multiply parentheses

6x^2-4x

Back to the equation:

-(6x^2-4x)


We get rid of parentheses

-6x^2+4x+42=0

a = -6; b = 4; c = +42;
Δ = b2-4ac
Δ = 42-4·(-6)·42
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-32}{2*-6}=\frac{-36}{-12}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+32}{2*-6}=\frac{28}{-12}
=-2+1/3
$