425-(3x+3(x+5))=20

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Solution for 425-(3x+3(x+5))=20 equation: 



425-(3x+3(x+5))=20

We move all terms to the left:

425-(3x+3(x+5))-(20)=0

We add all the numbers together, and all the variables

-(3x+3(x+5))+405=0



We calculate terms in parentheses: -(3x+3(x+5)), so:

3x+3(x+5)

We multiply parentheses

3x+3x+15

We add all the numbers together, and all the variables

6x+15

Back to the equation:

-(6x+15)



We get rid of parentheses

-6x-15+405=0

We add all the numbers together, and all the variables

-6x+390=0

We move all terms containing x to the left, all other terms to the right

-6x=-390

x=-390/-6

x=+65

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