42/k-5=3

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Solution for 42/k-5=3 equation: 



42/k-5=3

We move all terms to the left:

42/k-5-(3)=0



Domain of the equation: k!=0

k∈R



We add all the numbers together, and all the variables

42/k-8=0

We multiply all the terms by the denominator


-8*k+42=0

We add all the numbers together, and all the variables

-8k+42=0

We move all terms containing k to the left, all other terms to the right

-8k=-42

k=-42/-8

k=5+1/4

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