42-(3c+4)=2c+14+c

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Solution for 42-(3c+4)=2c+14+c equation: 



42-(3c+4)=2c+14+c

We move all terms to the left:

42-(3c+4)-(2c+14+c)=0

We add all the numbers together, and all the variables

-(3c+4)-(3c+14)+42=0

We get rid of parentheses

-3c-3c-4-14+42=0

We add all the numbers together, and all the variables

-6c+24=0

We move all terms containing c to the left, all other terms to the right

-6c=-24

c=-24/-6

c=+4

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