42-(2c+3)=4(c+7)+c

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Solution for 42-(2c+3)=4(c+7)+c equation: 



42-(2c+3)=4(c+7)+c

We move all terms to the left:

42-(2c+3)-(4(c+7)+c)=0

We get rid of parentheses

-2c-(4(c+7)+c)-3+42=0



We calculate terms in parentheses: -(4(c+7)+c), so:

4(c+7)+c

We add all the numbers together, and all the variables

c+4(c+7)

We multiply parentheses

c+4c+28

We add all the numbers together, and all the variables

5c+28

Back to the equation:

-(5c+28)



We add all the numbers together, and all the variables

-2c-(5c+28)+39=0

We get rid of parentheses

-2c-5c-28+39=0

We add all the numbers together, and all the variables

-7c+11=0

We move all terms containing c to the left, all other terms to the right

-7c=-11

c=-11/-7

c=1+4/7

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