42(x+3)=x-4

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Solution for 42(x+3)=x-4 equation: 



42(x+3)=x-4

We move all terms to the left:

42(x+3)-(x-4)=0

We multiply parentheses

42x-(x-4)+126=0

We get rid of parentheses

42x-x+4+126=0

We add all the numbers together, and all the variables

41x+130=0

We move all terms containing x to the left, all other terms to the right

41x=-130

x=-130/41

x=-3+7/41

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