41x=2(3x+35)

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Solution for 41x=2(3x+35) equation: 



41x=2(3x+35)

We move all terms to the left:

41x-(2(3x+35))=0



We calculate terms in parentheses: -(2(3x+35)), so:

2(3x+35)

We multiply parentheses

6x+70

Back to the equation:

-(6x+70)



We get rid of parentheses

41x-6x-70=0

We add all the numbers together, and all the variables

35x-70=0

We move all terms containing x to the left, all other terms to the right

35x=70

x=70/35

x=2

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