41c+18=5c+9(2+4c)

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Solution for 41c+18=5c+9(2+4c) equation: 



41c+18=5c+9(2+4c)

We move all terms to the left:

41c+18-(5c+9(2+4c))=0

We add all the numbers together, and all the variables

41c-(5c+9(4c+2))+18=0



We calculate terms in parentheses: -(5c+9(4c+2)), so:

5c+9(4c+2)

We multiply parentheses

5c+36c+18

We add all the numbers together, and all the variables

41c+18

Back to the equation:

-(41c+18)



We get rid of parentheses

41c-41c-18+18=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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