41=z/3+33

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Solution for 41=z/3+33 equation: 



41=z/3+33

We move all terms to the left:

41-(z/3+33)=0

We get rid of parentheses

-z/3-33+41=0

We multiply all the terms by the denominator


-z-33*3+41*3=0

We add all the numbers together, and all the variables

-1z+24=0

We move all terms containing z to the left, all other terms to the right

-z=-24

z=-24/-1

z=+24

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