41=7(3b+2)+3(-56+1)

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Solution for 41=7(3b+2)+3(-56+1) equation: 



41=7(3b+2)+3(-56+1)

We move all terms to the left:

41-(7(3b+2)+3(-56+1))=0

We add all the numbers together, and all the variables

-(7(3b+2)+3(-55))+41=0



We calculate terms in parentheses: -(7(3b+2)+3(-55)), so:

7(3b+2)+3(-55)

We add all the numbers together, and all the variables

7(3b+2)-165

We multiply parentheses

21b+14-165

We add all the numbers together, and all the variables

21b-151

Back to the equation:

-(21b-151)



We get rid of parentheses

-21b+151+41=0

We add all the numbers together, and all the variables

-21b+192=0

We move all terms containing b to the left, all other terms to the right

-21b=-192

b=-192/-21

b=9+1/7

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