41=-7(z-3)z=

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Solution for 41=-7(z-3)z= equation: 



41=-7(z-3)z=

We move all terms to the left:

41-(-7(z-3)z)=0



We calculate terms in parentheses: -(-7(z-3)z), so:

-7(z-3)z

We multiply parentheses

-7z^2+21z

Back to the equation:

-(-7z^2+21z)



We get rid of parentheses

7z^2-21z+41=0

a = 7; b = -21; c = +41;
Δ = b2-4ac
Δ = -212-4·7·41
Δ = -707
Delta is less than zero, so there is no solution for the equation

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