41-(2c+4)=2(c+6)+c

Solution for 41-(2c+4)=2(c+6)+c equation:

Simplifying
41 + -1(2c + 4) = 2(c + 6) + c

Reorder the terms:
41 + -1(4 + 2c) = 2(c + 6) + c
41 + (4 * -1 + 2c * -1) = 2(c + 6) + c
41 + (-4 + -2c) = 2(c + 6) + c

Combine like terms: 41 + -4 = 37
37 + -2c = 2(c + 6) + c

Reorder the terms:
37 + -2c = 2(6 + c) + c
37 + -2c = (6 * 2 + c * 2) + c
37 + -2c = (12 + 2c) + c

Combine like terms: 2c + c = 3c
37 + -2c = 12 + 3c

Solving
37 + -2c = 12 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
37 + -2c + -3c = 12 + 3c + -3c

Combine like terms: -2c + -3c = -5c
37 + -5c = 12 + 3c + -3c

Combine like terms: 3c + -3c = 0
37 + -5c = 12 + 0
37 + -5c = 12

Add '-37' to each side of the equation.
37 + -37 + -5c = 12 + -37

Combine like terms: 37 + -37 = 0
0 + -5c = 12 + -37
-5c = 12 + -37

Combine like terms: 12 + -37 = -25
-5c = -25

Divide each side by '-5'.
c = 5

Simplifying
c = 5