41+8x=3(10x-1)

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Solution for 41+8x=3(10x-1) equation: 



41+8x=3(10x-1)

We move all terms to the left:

41+8x-(3(10x-1))=0



We calculate terms in parentheses: -(3(10x-1)), so:

3(10x-1)

We multiply parentheses

30x-3

Back to the equation:

-(30x-3)



We get rid of parentheses

8x-30x+3+41=0

We add all the numbers together, and all the variables

-22x+44=0

We move all terms containing x to the left, all other terms to the right

-22x=-44

x=-44/-22

x=+2

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