41+3x=2(49-8x)

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Solution for 41+3x=2(49-8x) equation: 



41+3x=2(49-8x)

We move all terms to the left:

41+3x-(2(49-8x))=0

We add all the numbers together, and all the variables

3x-(2(-8x+49))+41=0



We calculate terms in parentheses: -(2(-8x+49)), so:

2(-8x+49)

We multiply parentheses

-16x+98

Back to the equation:

-(-16x+98)



We get rid of parentheses

3x+16x-98+41=0

We add all the numbers together, and all the variables

19x-57=0

We move all terms containing x to the left, all other terms to the right

19x=57

x=57/19

x=3

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