41+(3x=4)=8x

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Solution for 41+(3x=4)=8x equation: 



41+(3x=4)=8x

We move all terms to the left:

41+(3x-(4))=0

We get rid of parentheses

3x-4+41=0

We add all the numbers together, and all the variables

3x+37=0

We move all terms containing x to the left, all other terms to the right

3x=-37

x=-37/3

x=-12+1/3

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