40y-15=5(8y-3)

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Solution for 40y-15=5(8y-3) equation:



40y-15=5(8y-3)
We move all terms to the left:
40y-15-(5(8y-3))=0
We calculate terms in parentheses: -(5(8y-3)), so:
5(8y-3)
We multiply parentheses
40y-15
Back to the equation:
-(40y-15)
We get rid of parentheses
40y-40y+15-15=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0

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