40x-48=21x+12

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Solution for 40x-48=21x+12 equation: 



40x-48=21x+12

We move all terms to the left:

40x-48-(21x+12)=0

We get rid of parentheses

40x-21x-12-48=0

We add all the numbers together, and all the variables

19x-60=0

We move all terms containing x to the left, all other terms to the right

19x=60

x=60/19

x=3+3/19

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