40x-19=-8/1(-5x-6)

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Solution for 40x-19=-8/1(-5x-6) equation: 


x in (-oo:+oo)

40*x-19 = (-8/1)*(-5*x-6) // - (-8/1)*(-5*x-6)

40*x-((-8/1)*(-5*x-6))-19 = 0

8*(-5*x-6)+40*x-19 = 0

8*(-5*x-6)+40*x-19 = 0

-48-19 = 0

-67 = 0

-67 = 0

-67 = 0

x belongs to the empty set

x belongs to the empty set

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