40x+15(100-x)=33

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Solution for 40x+15(100-x)=33 equation: 



40x+15(100-x)=33

We move all terms to the left:

40x+15(100-x)-(33)=0

We add all the numbers together, and all the variables

40x+15(-1x+100)-33=0

We multiply parentheses

40x-15x+1500-33=0

We add all the numbers together, and all the variables

25x+1467=0

We move all terms containing x to the left, all other terms to the right

25x=-1467

x=-1467/25

x=-58+17/25

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