40p(p-1)=39p

Solution for 40p(p-1)=39p equation:

40p(p-1)=39p

We move all terms to the left:

40p(p-1)-(39p)=0

We add all the numbers together, and all the variables

-39p+40p(p-1)=0

We multiply parentheses

40p^2-39p-40p=0

We add all the numbers together, and all the variables

40p^2-79p=0

a = 40; b = -79; c = 0;
Δ = b2-4ac
Δ = -792-4·40·0
Δ = 6241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6241}=79$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-79)-79}{2*40}=\frac{0}{80}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-79)+79}{2*40}=\frac{158}{80}
=1+39/40
$