40=x2+3x-1

Solution for 40=x2+3x-1 equation:

40=x2+3x-1

We move all terms to the left:

40-(x2+3x-1)=0

We add all the numbers together, and all the variables

-(+x^2+3x-1)+40=0

We get rid of parentheses

-x^2-3x+1+40=0

We add all the numbers together, and all the variables

-1x^2-3x+41=0

a = -1; b = -3; c = +41;
Δ = b2-4ac
Δ = -32-4·(-1)·41
Δ = 173
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{173}}{2*-1}=\frac{3-\sqrt{173}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{173}}{2*-1}=\frac{3+\sqrt{173}}{-2}
$