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40=x*2x
We move all terms to the left:
40-(x*2x)=0
We add all the numbers together, and all the variables
-(+x*2x)+40=0
We get rid of parentheses
-x*2x+40=0
Wy multiply elements
-2x^2+40=0
a = -2; b = 0; c = +40;
Δ = b2-4ac
Δ = 02-4·(-2)·40
Δ = 320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{320}=\sqrt{64*5}=\sqrt{64}*\sqrt{5}=8\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{5}}{2*-2}=\frac{0-8\sqrt{5}}{-4} =-\frac{8\sqrt{5}}{-4} =-\frac{2\sqrt{5}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{5}}{2*-2}=\frac{0+8\sqrt{5}}{-4} =\frac{8\sqrt{5}}{-4} =\frac{2\sqrt{5}}{-1} $
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