40=5+3(t-2)

Solution for 40=5+3(t-2) equation:

40=5+3(t-2)

We move all terms to the left:

40-(5+3(t-2))=0


We calculate terms in parentheses: -(5+3(t-2)), so:

5+3(t-2)

determiningTheFunctionDomain
3(t-2)+5

We multiply parentheses

3t-6+5

We add all the numbers together, and all the variables

3t-1

Back to the equation:

-(3t-1)


We get rid of parentheses

-3t+1+40=0

We add all the numbers together, and all the variables

-3t+41=0

We move all terms containing t to the left, all other terms to the right

-3t=-41

t=-41/-3

t=13+2/3