40=5(x-1)/3+2x

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Solution for 40=5(x-1)/3+2x equation: 



40=5(x-1)/3+2x

We move all terms to the left:

40-(5(x-1)/3+2x)=0



Domain of the equation: 3+2x)!=0

We move all terms containing x to the left, all other terms to the right

2x)!=-3

x!=-3/1

x!=-3

x∈R



We multiply all the terms by the denominator


-(5(x-1)+40*3+2x)=0



We calculate terms in parentheses: -(5(x-1)+40*3+2x), so:

5(x-1)+40*3+2x

determiningTheFunctionDomain
5(x-1)+2x+40*3

We add all the numbers together, and all the variables

2x+5(x-1)+120

We multiply parentheses

2x+5x-5+120

We add all the numbers together, and all the variables

7x+115

Back to the equation:

-(7x+115)



We get rid of parentheses

-7x-115=0

We move all terms containing x to the left, all other terms to the right

-7x=115

x=115/-7

x=-16+3/7

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