40=4(6+11n)+4(-8+n)

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Solution for 40=4(6+11n)+4(-8+n) equation: 



40=4(6+11n)+4(-8+n)

We move all terms to the left:

40-(4(6+11n)+4(-8+n))=0

We add all the numbers together, and all the variables

-(4(11n+6)+4(n-8))+40=0



We calculate terms in parentheses: -(4(11n+6)+4(n-8)), so:

4(11n+6)+4(n-8)

We multiply parentheses

44n+4n+24-32

We add all the numbers together, and all the variables

48n-8

Back to the equation:

-(48n-8)



We get rid of parentheses

-48n+8+40=0

We add all the numbers together, and all the variables

-48n+48=0

We move all terms containing n to the left, all other terms to the right

-48n=-48

n=-48/-48

n=1

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