40=3(x+2)-5

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Solution for 40=3(x+2)-5 equation: 



40=3(x+2)-5

We move all terms to the left:

40-(3(x+2)-5)=0



We calculate terms in parentheses: -(3(x+2)-5), so:

3(x+2)-5

We multiply parentheses

3x+6-5

We add all the numbers together, and all the variables

3x+1

Back to the equation:

-(3x+1)



We get rid of parentheses

-3x-1+40=0

We add all the numbers together, and all the variables

-3x+39=0

We move all terms containing x to the left, all other terms to the right

-3x=-39

x=-39/-3

x=+13

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